Applications of Integrals is one of the most practical chapters in Class 12 Maths, building directly on indefinite and definite integration. While definite integrals calculate the accumulation of quantities, the applications of integrals allow students to use integration for real-world problems such as:
Finding area under curves
Calculating the area between curves
Determining the volume of solids of revolution
Computing average value of a function
This chapter is highly scoring in JEE Main as it combines conceptual understanding with problem-solving techniques.
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Set Theory |
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Relation & Function |
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Trignometrical Ratios , Functions & Identities |
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4.1 |
Complex Numbers |
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Quadratic Equations & Inequations |
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linear Inequalities |
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Permutation & Combination |
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Binomial Theoram |
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Sequence & Series |
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Straight Line |
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Circle & System Of Circle |
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Parabola , Ellipse , Hyperbola |
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Introduction To Three Dimensional Geometry |
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Limits |
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Statistics |
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Probability |
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Basic Of Algoritham |
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Rectangular Cartensian Co-Ordinates |
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Trigonometrical Equations |
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Relation & Function |
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Inverse Trigonometric Function |
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Determinant & Metrices |
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Continuity & Differentiation |
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Application Of Derivatives |
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Inderfinite Integral |
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Definite Integral |
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Application & Integration |
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Differential Equations |
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Vector Algebra |
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Three Dimension Geometry |
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Linear Programming |
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Probability |
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Applications of Integrals is crucial for JEE Main because:
Questions often involve finding area, volume, or averages, which carry good marks.
Integration applications test both algebraic manipulation and conceptual clarity.
Understanding these applications helps in solving multi-step JEE Main problems efficiently.
Mastery of this chapter also prepares students for higher-level engineering and physics problems.
Students who excel in this chapter can tackle practical problems with confidence during exams.
Students must focus on the following key areas:
Area under Curves y = f(x) and y = g(x):
Area under a curve from x = a to x = b: A = ∫[a to b] f(x) dx
Area between two curves: A = ∫[a to b] [f(x) − g(x)] dx
Area in the y-axis direction:
Area between curves with respect to y: A = ∫[c to d] [x₂(y) − x₁(y)] dy
Volume of Solids of Revolution:
Around x-axis: V = π ∫[a to b] [f(x)]² dx
Around y-axis: V = π ∫[c to d] [g(y)]² dy
Average Value of a Function:
Average value over [a, b]: f_avg = (1/(b − a)) ∫[a to b] f(x) dx
Connection with Definite Integrals:
All applications use definite integrals and properties like linearity and symmetry.
Real-life Applications:
Motion, area, engineering, economics, and physics problems.
Class 12 Applications of Integrals problems in JEE Main generally include:
Area under Curve Problems:
Calculate area under standard curves like y = x², y = sin x, y = e^x.
Area between Two Curves:
Solve problems using A = ∫[a to b] [f(x) − g(x)] dx or in terms of y.
Volume of Solids of Revolution:
Rotate curves around x-axis or y-axis to find volumes of cylinders, cones, and irregular solids.
Average Value of Functions:
Compute average using f_avg = (1/(b − a)) ∫[a to b] f(x) dx.
Advanced JEE-Level Problems:
Combine multiple applications, e.g., area and volume in a single problem.
Use substitution, symmetry, or trigonometric identities for simplification.
For JEE Main, students should follow this approach:
Understand the Problem Type:
Identify whether it involves area, volume, or average value.
Set Up the Integral:
Use limits a to b (or c to d) according to the problem.
Simplify the Function:
Factor, expand, or use trigonometric identities if needed.
Integrate Carefully:
Solve the integral step by step, applying standard formulas and properties.
Apply Constants and Multipliers:
Include π for volumes, or 1/(b − a) for average value.
Check Geometric or Physical Sense:
Ensure the answer is positive for areas and volumes; verify correctness using symmetry if applicable.
Memorize formulas for volume of solids of revolution.
Use symmetry to simplify area and volume problems.
Convert problems in y-axis if it simplifies the integral.
Solve previous years’ JEE Main problems for practical familiarity.
Break complex integrals into sums or differences of simpler definite integrals.
Example 1: Area under y = x² from x = 0 to x = 2
Solution: A = ∫[0 to 2] x² dx = [x³/3]₀² = 8/3
Example 2: Area between y = x² and y = x from x = 0 to x = 1
Solution: A = ∫[0 to 1] (x − x²) dx = [x²/2 − x³/3]₀¹ = 1/2 − 1/3 = 1/6
Example 3: Volume of solid generated by rotating y = x² around x-axis from x = 0 to 1
Solution: V = π ∫[0 to 1] (x²)² dx = π ∫[0 to 1] x⁴ dx = π [x⁵/5]₀¹ = π/5
Example 4: Average value of f(x) = x² over [0, 2]
Solution: f_avg = (1/2 − 0) ∫[0 to 2] x² dx = (1/2) * [x³/3]₀² = (1/2) * (8/3) = 4/3
NCERT Class 12 Maths textbooks (Chapter: Applications of Integrals)
Previous years’ JEE Main question papers
Mock tests and online quizzes on Studentbro.in
Video lectures and solved examples for step-by-step learning
Applications of Integrals is a highly practical and scoring chapter for Class 12 students preparing for JEE Main. Mastery of this chapter:
Helps solve real-life problems involving area, volume, and averages efficiently.
Builds strong analytical, algebraic, and problem-solving skills.
Saves time in competitive exams with systematic integration strategies.
Prepares students for higher-level calculus, physics, and engineering applications.
With consistent practice, formula memorization, and careful evaluation strategies, Applications of Integrals can become one of the most scoring chapters in JEE Main Maths.