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Overview of Height & Distances in JEE Maths

Height and distance problems are an essential application of trigonometry in JEE Maths. These problems involve calculating the heights of objects, distances between objects, and angles of elevation and depression. At StudentBro.in, we provide a comprehensive guide with formulas, solution methods, examples, and practice questions to help JEE aspirants master height and distance problems efficiently for JEE Main & Advanced exams.


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Definition of Height & Distance Problems

Height and distance problems are trigonometric applications that involve:

  • Finding the height of objects like poles, towers, or buildings

  • Calculating distances between objects using angles of elevation and depression

  • Applying right triangle trigonometry in real-world scenarios

  • Example: From a point 50 m away from a tower, the angle of elevation to the top is 30°. Find the height of the tower.


Angle of Elevation

  • The angle of elevation is the angle formed by the line of sight of an observer looking upwards to an object above the horizontal line.

  • Formula using a right triangle:

    • tan θ = Opposite / Adjacent = Height / Distance

  • Important for calculating heights of buildings, trees, or towers

Example: If tan 30° = h / 50 → h = 50 × tan 30° = 50 × (1/√3) ≈ 28.87 m


Angle of Depression

  • The angle of depression is the angle formed by the line of sight of an observer looking downwards from a height to an object on the ground.

  • Similar formula applies:

    • tan θ = Opposite / Adjacent = Height / Distance

  • Widely used in coastal, airport, and observation tower problems

Example: If an observer sees a boat at 45° depression from a lighthouse 100 m tall → distance = 100 / tan 45° = 100 m


Formulas for Height & Distance Problems

  1. tan θ = Height / Distance

  2. Height = Distance × tan θ

  3. Distance = Height / tan θ

  • For two objects or multiple points of observation:

    • Use difference of heights and angles

    • Apply right triangle rules systematically


Solving Problems with Two Points of Observation

  • When an observer views the top of a tower from two different points on the same horizontal line, the height can be found using:

Formula:

h=d1d2(tan⁡θ1−tan⁡θ2)d2−d1h = \frac{d_1 d_2 (\tan θ_1 - \tan θ_2)}{d_2 - d_1}h=d2​−d1​d1​d2​(tanθ1​−tanθ2​)​

  • Where d1, d2 are distances from the tower and θ1, θ2 are angles of elevation

Example:

  • Observer sees the top of a tower at 30° from point A (20 m from tower) and 60° from point B (40 m from tower). Height: h = ...


Applications of Height & Distance Problems

  • Real-life applications in engineering, construction, surveying, and navigation

  • Helps in calculating tower heights, tree heights, and distances between objects

  • Applied in physics problems on projectile motion and inclined planes


Tips and Tricks for Solving Height & Distance Problems

  1. Draw a clear right triangle diagram with height, distance, and angle

  2. Label all known and unknown quantities

  3. Use tan θ = Height / Distance systematically

  4. For multiple points of observation, apply difference method or ratio method

  5. Solve previous JEE problems for speed and accuracy


StudentBro.in JEE Maths Height & Distance Section

At StudentBro.in, students can access:

  • Step-by-step explanations for angles of elevation and depression

  • Worked examples for single and two-point observations

  • Practice questions with solutions and shortcuts

  • Tips for quick diagram drawing and formula application

  • Revision notes for last-minute preparation


Practice Questions and Sample Problems

  1. From a point 30 m away from a tower, the angle of elevation to the top is 45°. Find the height of the tower.

  2. The angle of depression from a 50 m tall building to a car on the ground is 30°. Find the distance of the car from the base.

  3. An observer sees the top of a tower at 30° from one point and 60° from another point 50 m farther. Find the height of the tower.

  4. A man 2 m tall is 10 m away from a wall. Find the angle of elevation to the top of the wall.

  5. Two poles of heights 10 m and 15 m are 30 m apart. Find the angle of elevation to the top of the taller pole from the top of the shorter pole.

Regular practice improves accuracy, speed, and confidence in solving height and distance problems in JEE exams.


Conclusion

Height & Distance problems are a vital application of trigonometry in JEE Maths. Understanding angles of elevation, angles of depression, and right triangle formulas allows students to calculate heights and distances efficiently. At StudentBro.in, we provide a complete guide from basics to advanced problem-solving, making these problems easy, practical, and exam-oriented.

Mastering this topic ensures students can tackle all height and distance problems confidently in both JEE Main and Advanced exams.