Quadratic equations are one of the most important topics in JEE Maths. They appear in algebra, coordinate geometry, and calculus problems. A strong understanding of quadratic equations allows students to solve polynomial problems, find roots efficiently, and tackle competitive exam questions confidently. At StudentBro.in, we provide a comprehensive guide covering formulas, roots, factorization, discriminant, and practice problems for JEE aspirants.
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A quadratic equation is a polynomial equation of degree 2, represented as:
ax² + bx + c = 0, where a ≠ 0
a = coefficient of x²
b = coefficient of x
c = constant term
Roots of the equation are the values of x that satisfy the equation.
Example: x² - 5x + 6 = 0 → roots are x = 2, 3
There are several techniques to solve quadratic equations in JEE:
Factorization Method
Express the quadratic as a product of two binomials:
x² - 5x + 6 = (x - 2)(x - 3) = 0 → x = 2, 3
Useful for simple equations with integer roots
Quadratic Formula
x = [-b ± √(b² - 4ac)] / 2a
Works for all types of quadratic equations, including non-factorable ones
Completing the Square
Transform ax² + bx + c = 0 into a perfect square form:
x² + (b/a)x + (c/a) = 0 → (x + p)² = q
Graphical Method
Plot the quadratic equation y = ax² + bx + c to find roots where the graph intersects x-axis
Discriminant (D) = b² - 4ac
D > 0: Two real and distinct roots
D = 0: Two real and equal roots
D < 0: Two complex conjugate roots
Example: x² - 4x + 4 = 0 → D = 16 - 16 = 0 → Roots are equal: x = 2
For a quadratic equation ax² + bx + c = 0 with roots α and β:
Sum of roots: α + β = -b/a
Product of roots: αβ = c/a
These formulas help in forming quadratic equations with given roots and solving related problems.
Example: Form a quadratic equation with roots 3 and 5 → x² - 8x + 15 = 0
Real and Distinct Roots – Most basic problems
Real and Equal Roots – Often appears in symmetry and maximum/minimum problems
Complex Roots – Appears in higher-level algebra and polynomial problems
If b = 0 → x² + c = 0 → x = ±√(-c)
If c = 0 → ax² + bx = 0 → x(ax + b) = 0 → x = 0 or x = -b/a
Perfect square trinomials → shortcut for factorization:
x² + 2ax + a² = (x + a)²
These shortcuts save time in JEE Main and Advanced exams.
Solving word problems: Age, speed, distance, mixture
Maximizing or minimizing expressions using vertex formula x = -b/2a
Finding coordinates in coordinate geometry
Solving physics-related algebraic problems
Example: The sum of squares of two numbers is 25 and their product is 6. Find the numbers. → x² - 5x + 6 = 0 → x = 2, 3
Always check factorization possibility before using the formula
Memorize sum and product of roots formulas
Use discriminant to determine nature of roots quickly
Apply shortcuts for perfect square trinomials
Practice previous year JEE quadratic questions to improve speed
At StudentBro.in, students can access:
Step-by-step explanations for all types of quadratic problems
Worked examples with different methods: factorization, formula, completing the square
Practice problems with solutions and shortcuts
Tips for quick problem-solving and time management
Revision notes for last-minute preparation
Solve x² - 7x + 12 = 0
Solve 2x² + 5x - 3 = 0
Find roots of x² + 4x + 5 = 0 (complex roots)
Form a quadratic equation with roots 2 and -3
Solve x² - 2x = 15 using completing the square
Quadratic equations are a vital topic in JEE Maths. Understanding formulas, discriminant, sum and product of roots, and factorization allows students to solve problems efficiently. At StudentBro.in, we provide a complete guide covering basics to advanced problem-solving, making quadratic equations simple, practical, and exam-oriented.
Mastering quadratic equations ensures students can tackle algebraic, coordinate, and physics-based numerical problems confidently in both JEE Main and Advanced exams.