Progressions are one of the most scoring topics in JEE Maths. They allow students to analyze sequences of numbers with patterns and solve problems using formulas and shortcuts. At StudentBro.in, we provide a complete guide covering Arithmetic Progression (AP), Geometric Progression (GP), and Harmonic Progression (HP) with step-by-step explanations, formulas, examples, and practice questions to help JEE aspirants excel.
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A progression is a sequence of numbers arranged according to a specific rule or pattern.
Arithmetic Progression (AP): A sequence in which the difference between consecutive terms is constant.
Geometric Progression (GP): A sequence in which the ratio of consecutive terms is constant.
Harmonic Progression (HP): A sequence in which the reciprocals of the terms form an arithmetic progression.
Example:
AP: 2, 5, 8, 11 (common difference = 3)
GP: 3, 6, 12, 24 (common ratio = 2)
HP: 1, 1/3, 1/5, 1/7 (reciprocals form an AP)
Definition: A sequence where the difference between consecutive terms is constant (d).
General Term (nth term):
Tₙ = a + (n - 1)d
Sum of n Terms:
Sₙ = n/2 [2a + (n - 1)d] = n/2 (a + l)
Where:
a = first term
d = common difference
l = last term
n = number of terms
Applications in JEE:
Finding nth term of sequences
Sum of numbers in series
Solving word problems involving age, salary, or distances
Example: Find the 10th term of AP: 2, 5, 8, …
T₁₀ = 2 + (10-1)*3 = 29
Definition: A sequence where each term after the first is obtained by multiplying the previous term by a constant (r).
General Term (nth term):
Tₙ = a * r^(n-1)
Sum of n Terms:
Sₙ = a (rⁿ - 1) / (r - 1), r ≠ 1
Sum to Infinity (|r| < 1):
S∞ = a / (1 - r)
Applications in JEE:
Compound interest problems
Population growth and decay
Series sum problems in advanced questions
Example: GP: 2, 6, 18, …; 5th term = 2 * 3⁴ = 162
Definition: A sequence in which reciprocals of the terms form an arithmetic progression.
HP term: If 1/T₁, 1/T₂, … form an AP, then the sequence is HP.
Relation to AP:
Convert HP to AP using reciprocals
Solve sum and term problems using AP formulas
Example: 1, 1/3, 1/5, … → reciprocals 1, 3, 5 form an AP
AP Formulas:
Tₙ = a + (n-1)d
Sₙ = n/2 [2a + (n-1)d]
GP Formulas:
Tₙ = a * r^(n-1)
Sₙ = a(rⁿ - 1)/(r - 1), r ≠ 1
S∞ = a / (1 - r), |r| < 1
HP Formulas:
Convert to AP: 1/Tₙ = a + (n-1)d
Sum and nth term derived using AP relations
Memorize AP, GP, HP formulas thoroughly
Practice nth term and sum problems daily
Convert HP to AP to simplify problems
Learn shortcuts for sum of series questions
Solve previous year JEE progression problems for speed
AP: Age-related, salary, distance, or time problems
GP: Compound interest, population growth, decay problems
HP: Series involving reciprocals in physics or math word problems
Many mixed progression problems combine AP, GP, and HP
Example: A train covers distances in AP: 10, 15, 20 … Find distance covered in 12th interval.
At StudentBro.in, students can access:
Step-by-step explanations of AP, GP, HP formulas
Worked examples for each type of progression
Practice problems with solutions and shortcuts
Tips for quick calculation and exam strategy
Revision notes for last-minute preparation
Find the 20th term of AP: 3, 7, 11, …
Sum of first 15 terms of AP: 5, 8, 11, …
Find the 6th term of GP: 2, 4, 8, …
Sum to infinity of GP: 3, 3/2, 3/4, …
Find 4th term of HP: 1, 1/3, 1/5, …
Regular practice improves accuracy, speed, and confidence in solving progression problems.
Progressions are a high-scoring chapter in JEE Maths. Understanding AP, GP, and HP formulas, combined with practice, allows students to solve problems quickly and accurately. At StudentBro.in, we provide a complete guide from basics to advanced problem-solving, making progressions simple and exam-oriented.
Mastering progressions ensures students can tackle numerical and series problems confidently in both JEE Main and Advanced exams.