Permutations and Combinations (P&C) form a key part of the Counting Principle in JEE Maths. They help students solve problems related to arrangements, selections, and probability. Understanding P&C is essential for both JEE Main and Advanced exams, as many high-scoring problems are based on these concepts. At StudentBro.in, we provide a comprehensive guide covering formulas, examples, tricks, and practice problems to help students master this topic efficiently.
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Permutation: Arrangement of objects in a specific order. Order matters.
Combination: Selection of objects without considering order. Order does not matter.
Example:
Permutation: Arrange A, B, C → ABC, ACB, BAC …
Combination: Choose 2 from A, B, C → AB, AC, BC
Factorial: n! = n × (n-1) × … × 2 × 1
Counting Principle: Total ways = Product of choices at each stage
Example: Selecting a 2-digit number from digits 1, 2, 3 → 3 × 2 = 6
Number of ways to arrange r objects from n objects:
nPr = n! / (n-r)!
Applications:
Arrangements of letters, digits, or objects in order
Circular arrangements and repeated objects
Example: Arrange 3 letters from A, B, C, D → 4P3 = 4! / (4-3)! = 24
Number of ways to select r objects from n objects (order does not matter):
nCr = n! / [r!(n-r)!]
Applications:
Selection problems in teams or committees
Choosing objects without regard to order
Example: Select 2 students from 4 → 4C2 = 6
nPr = nCr × r!
This relation is useful for switching between counting arrangements and selections efficiently.
Example: 4P2 = 4C2 × 2! = 6 × 2 = 12
Repetition allowed: nⁿ arrangements
Circular permutation: (n-1)!
Permutation with identical objects: n! / (p! q! …)
Example: Arranging letters of "LEVEL" → 5! / (2! 2!) = 30
Selections with restrictions – Include or exclude certain objects
Using symmetry property: nCr = nC(n-r)
Multiple groups selection: Use product of combinations
Example: Choose 3 from 5 boys and 2 girls → 5C3 × 2C2 = 10 × 1 = 10
Arrangement problems: Seats, digits, letters
Selection problems: Teams, committees
Probability problems: Favorable outcomes / Total outcomes
Word formation and repeated letter arrangements
Circular arrangements for competitive exam problems
Memorize factorial, nPr, nCr formulas
Check if order matters → Permutation vs Combination
Use symmetry and repetition shortcuts
Apply product rule and counting principle in multi-step problems
Solve previous year JEE P&C problems for accuracy and speed
Permutation Formulas:
nPr = n! / (n-r)!
Circular permutation: (n-1)!
Permutation with repetition: nⁿ
Permutation of identical objects: n! / (p! q! …)
Combination Formulas:
nCr = n! / [r!(n-r)!]
nCr = nC(n-r)
Multiple group selection: nCk × mCl
At StudentBro.in, students can access:
Step-by-step explanations for all P&C problems
Worked examples for arrangements, selections, circular problems, and repeated objects
Practice questions with solutions and shortcuts
Tips for quick problem-solving and exam strategy
Revision notes for last-minute preparation
Arrange 3 letters from A, B, C, D → How many ways?
Select 2 students from 5 boys and 3 girls → How many ways?
Arrange letters of "BALLOON" → Repeated letters
Circular arrangement of 6 people → How many ways?
Probability problem: 2 students are selected from 5 boys, 3 girls → Probability both are girls
Regular practice improves accuracy, speed, and confidence in solving P&C problems in JEE exams.
Permutations and Combinations are a high-scoring chapter in JEE Maths. Understanding factorials, nPr, nCr, and special cases allows students to solve arrangement, selection, and probability problems quickly and accurately. At StudentBro.in, we provide a complete guide from basics to advanced problem-solving, making P&C simple, practical, and exam-oriented.
Mastering P&C ensures students can tackle counting and probability questions confidently in both JEE Main and Advanced exams.